Also, anything like a^(log(c) / log(a)), for positive rational c and irrational a, to generalize bean_jamming's answer
I also assert without proof that in the equation x^x = c, x is irrational for most rational values of c
I did start trying out stuff with sqrt(2), thinking back to the tower power problems, but didn't end up coming up with your solution while doing so ¯\_(ツ)_/¯
:::
4 Comments
been_jamming@lemm.ee · 6 pts · 2y
e^(log 2) = 2 is rational
siriusmart@lemmy.world · 5 pts · 2y
that is simply genius
(i suppose it didnt come to me when i think of "irrational")
siriusmart@lemmy.world · 4 pts · 2y
this one got some table slams from my friends
Hint:
::: spoiler spoiler Find an example which satisfies the equation. :::
Solution:
::: spoiler spoiler https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd%20solutions/2024-05-13_irrational-powers.html
:::
zkfcfbzr@lemmy.world · 1 pts · 2y
::: spoiler solution e^(i*π) = -1
Also, anything like a^(log(c) / log(a)), for positive rational c and irrational a, to generalize bean_jamming's answer
I also assert without proof that in the equation x^x = c, x is irrational for most rational values of c
I did start trying out stuff with sqrt(2), thinking back to the tower power problems, but didn't end up coming up with your solution while doing so ¯\_(ツ)_/¯ :::