What are some complicated ways to write 1+1?

Kinda like (2/2)+(3/3) but way more complicated

12 points · 12 comments · view on lemmy.world

12 Comments

theKalash@feddit.ch · 9 pts · 2y (1 reply)

abs(e^iπ^) + abs(i^2^)

Kuba@programming.dev · 4 pts · 2y

Thanks

rasensprenger@feddit.de · 8 pts · 2y (1 reply)
\tan(\pi/4) + 1/42 \int_{-7\ln 6}^\infty \exp(-x/7) \dd{x}
rasensprenger@feddit.de · 10 pts · 2y

TheOrs@lemmy.world · 8 pts · 2y

The standard way when using ordinal arithmetic is: Take the ordinal 1, which is {{}}. Replace each element with a ordered pair of the form {{a},{a,b}} with second element being 0 (that is {}). Repeat with second element 1. Take a union. Take find the ordinal with this order. Overall: otp({ {{{}},{{},{}}}, {{{}},{{},{{}}}} }) Or simplified

otp({ {{{}}}, {{{}},{{},{{}}}} })

slazer2au@lemmy.world · 7 pts · 2y
MonkderZweite@feddit.ch · 3 pts · 2y

Most of them.

dbaner@lemmy.world · 2 pts · 2y

I saw somewhere that someone had decoded how an AI had learnt to do basic arithmetic. And it appeared to be using a massive expression containing lots of sin & cosines to do basic addition

Spzi@lemm.ee · 2 pts · 2y

(10^googol^)^0^ + (TREE(3))^0^

Although that's fairly easy to write. It's hard to calculate, if you calculate the brackets first.

pancake@lemmygrad.ml · 1 pts · 2y

(fix add a b := match a with O => b | S x => add x (S b) end) (S O) (S O)

Artisian@lemmy.world · 1 pts · 2y

Perhaps: (lim_{n->\infty} \sum_{m=1}^n 1/2^m ) + dim(Im(matrix([1,3,4],[2,6,8],[3,9,12])))

electrogamerman@lemmy.world · -1 pts · 2y

Pi/pi + pi/pi