Leibnitz Integral [rule]

73 points · 3 comments · view on lemmy.world

3 Comments

bh11235@infosec.pub · 12 pts · 2y (1 reply)
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lgstarn@kbin.social · 2 pts · 2y

For number 4 (or maybe a new number), if a(x) and b(x) are constant, the derivatives d/dx a(x) and d/dx b(x) are zero, so all that is left is that d/dx becomes a partial derivative and can move inside the integral.

genoxidedev1@lemmy.blahaj.zone · 10 pts · 2y
OmegaMouse@feddit.uk · 6 pts · 2y

Leibnitz nuts