c/196 · by theFibonacciEffect@feddit.de · 2yLeibnitz Integral [rule] 73 points · 3 comments · view on lemmy.world
3 Comments
bh11235@infosec.pub · 12 pts · 2y
lgstarn@kbin.social · 2 pts · 2y
For number 4 (or maybe a new number), if a(x) and b(x) are constant, the derivatives d/dx a(x) and d/dx b(x) are zero, so all that is left is that d/dx becomes a partial derivative and can move inside the integral.
genoxidedev1@lemmy.blahaj.zone · 10 pts · 2y
As a German, whenever I hear that term I think of this
OmegaMouse@feddit.uk · 6 pts · 2y
Leibnitz nuts