return !(x < y);
Assuming x and y are totally ordered 🤮
return (x >= y); also works
return (x >= y);
Something something sufficiently advanced compiler should optimize it away
5 Comments
LordTCup@lemmy.ca · 5 pts · 3y
return !(x < y);qwop@programming.dev · 3 pts · 3y
Assuming x and y are totally ordered 🤮
Beanie@programming.dev · 2 pts · 3y
return (x >= y);also worksJackbyDev@programming.dev · 4 pts · 3y
Something something sufficiently advanced compiler should optimize it away