🎲 - 2023 DAY 24 SOLUTIONS - 🎲

Day 24: Odds

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FAQ

8 points · 2 comments · view on lemmy.world

2 Comments

Treeniks@lemmy.ml · 2 pts · 2y

Rust

github: https://github.com/Treeniks/advent-of-code/blob/master/2023/day24/rust/src/main.rs

codeberg: https://codeberg.org/Treeniks/advent-of-code/src/branch/master/2023/day24/rust/src/main.rs

gitlab: https://gitlab.com/Treeniks/advent-of-code/-/blob/master/2023/day24/rust/src/main.rs

Had to look on reddit for how to solve part 2. Wasn't happy with the idea of using something like Z3, so I ended up brute force guessing the velocity, solving for the position and time and seeing if those are correct.

Lots of unintelligible calculations for solving the equation systems in the code that I just prepared on paper and transferred over.

cvttsd2si@programming.dev · 2 pts · 2y

Scala3, Sympy

case class Particle(x: Long, y: Long, z: Long, dx: Long, dy: Long, dz: Long)

def parseParticle(a: String): Option[Particle] = a match
    case s"$x, $y, $z @ $dx, $dy, $dz" => Some(Particle(x.toLong, y.toLong, z.toLong, dx.trim.toLong, dy.trim.toLong, dz.trim.toLong))
    case _ => None

def intersect(min: Double, max: Double)(p: Particle, q: Particle): Boolean =
    val n = p.dx * q.y - p.y * p.dx - q.x * p.dy + p.x * p.dy
    val d = p.dy * q.dx - p.dx * q.dy

    if(d == 0) then false else 
        val k = n.toDouble/d
        val k2 = (q.y + k * q.dy - p.y)/p.dy
        val ix = q.x + k * q.dx
        val iy = q.y + k * q.dy
        k2 >= 0 && k >= 0 && min <= ix && ix <= max && min <= iy && iy <= max

def task1(a: List[String]): Long = 
    val particles = a.flatMap(parseParticle)
    particles.combinations(2).count(l => intersect(2e14, 4e14)(l(0), l(1)))
import re as re2
from sympy import *

p, v, times, eqs = symbols('x y z'), symbols('dx dy dz'), [], []

def parse_eq(i: int, s: str):
    parts = [int(p) for p in re2.split(r'[,\s@]+', s) if p.strip() != '']
    time = Symbol(f't{i}')
    times.append(time)
    for rp, rv, hp, hv in zip(p, v, parts[:3], parts[3:]):
        eqs.append(Eq(rp + time * rv, hp + time * hv))

# need 3 equations for result, everything after that just slows things down
neq = 3
with open('task1.txt', 'r') as fobj:
    for i, s in zip(range(neq), fobj.readlines()):
        parse_eq(i, s)

for sol in solve(eqs, list(p) + list(v) + times):
    x, y, z, *_ = sol
    print(x + y + z)
hades@lemm.ee · 1 pts · 2y
[ removed ]