Imalostmerchant

u/Imalostmerchant@lemmy.world
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on *Permanently Deleted* · c/technology · 14 pts · 2y

If you don't know the difference between a resistor and a transistor, I'm not taking your advice on semiconductor companies

At the risk of defending the guy with the bad take, op can afford shelter and food. Op can't afford shelter and food and 1000 dollars of loan payments per month.

I hear you. You make very good points.

I'm tempted to argue that many humans aren't generally intelligent based on your definition of requiring original thought/solving things they haven't been told/trained on, but we don't have to go there. Lol

Can you expand on your last paragraph? You're saying if the model was trained on more theory and less examples of solved problems it might be improved?

The difference between 3.5 and 4 is substantial. Here is what 4 says

To find the number of combinations in which four friends (A, B, C, and D) can stand in line such that A and C are not next to each other, we can use the following approach:

  1. Total Combinations: First, calculate the total number of ways in which four people can be arranged in a line. This can be calculated by (4!) (4 factorial), since there are 4 slots to fill, each choice reducing the number of available choices by one for the next slot. [ 4! = 4 \times 3 \times 2 \times 1 = 24 ]

  2. Unwanted Combinations (Where A and C are next to each other):

    • Consider A and C as a single unit. This effectively reduces the number of units to arrange from 4 to 3 (the AC unit, B, and D).
    • These three units can be arranged in (3!) ways: [ 3! = 3 \times 2 \times 1 = 6 ]
    • However, within the AC unit, A and C can switch places. So, there are 2 ways to arrange A and C within their unit.
    • Therefore, the total number of arrangements where A and C are next to each other is: [ 3! \times 2 = 6 \times 2 = 12 ]
  3. Subtracting Unwanted Combinations: Subtract the number of unwanted combinations (where A and C are next to each other) from the total number of combinations: [ 24 - 12 = 12 ]

Thus, there are 12 combinations where A and C are not next to each other.

What are the actual ticker symbols of your investments? Agree with the other user that something isn't adding up here. You're likely not invested in what you think you are

on FF Evangelists · c/lemmyshitpost · 1 pts · 2y

Everyone uses multiple programs. Who said you'd only have one program open?

Using 40% for one of your most important programs seems totally reasonable to me.

I appreciate you taking the time to respond so thoughtfully.

I hear what you're saying about not firing someone until an actual effect on the business is felt. I think that makes sense in this situation but there's certainly situations where you could find something out about an employee and should be able to fire them before it's affecting the business. Maybe my accountant committed tax fraud when they filed their taxes. That's totally in their personal life and if no one finds out about it, then it doesn't affect the bussiness. I still think it would be totally reasonable to fire that person.

I've worked my whole career in salary positions where side gigs are against my contract/need special approval so I think I'm just used to that way of thinking.