This was a rare moment where I actually had to think to find it. Can you?
Screenshot is from a solver I found online because I didn't think to take a screenshot until I already opened the safe square.
Interesting position with a safe square - can you find it?
8 Comments
brian@lemmy.ca · 3 pts · 2y
It's interesting to see two answers having directly opposing answers.
But I do believe >!the 4/2/1 corner must be a bomb, the one above must be safe!<
NeatNit@discuss.tchncs.de · 3 pts · 2y
That is correct! The spoiler markdown doesn't work on my end (browser on desktop) but the others didn't even bother, so no matter!
GCanuck@lemmy.world · 1 pts · 2y
Top blank square. The two 1’s at the bottom prove it. Bottom 1 has two unknowns. Which means one of them is the bomb. Which means the bottom mystery square can’t be the bomb which means the top square is the bomb.
Euphorazine@lemmy.world · 1 pts · 2y
The corner of 1,2,4 on the left must be a bomb.
In the bottom gap, either side of the 1 being a bomb causes the 1,2,4 corner to be a bomb.
If the bomb is right of the 1, then the square above and below the 4 must be bombs because of the 2.
If the bomb is to the left of 1, the 2,2,3,3 forces one of the squares below the second 2 to be a bomb, which means the square below the 4 must be safe, so the square above 4 must be a bomb.
brian@lemmy.ca · 1 pts · 2y
If the bomb is to the left of the one, there could still be another bomb directly next to it, no?
Euphorazine@lemmy.world · 2 pts · 2y
No, the 3 below the two 1s has a shared partner with the 2 to it's left. So because it has a bomb directly above it, it must have one more below it. Therefore the space under the 4 would be empty and the space above it would have to be a bomb for the upper 2.
brian@lemmy.ca · 1 pts · 2y
Got it now, you're very right. I didn't evaluate that 3 correctly at all.
Flagstaff@programming.dev · 1 pts · 1y
The highest 2 has a mine to its left due to the 2 and 1 below it.
DrBob@lemmy.ca · 1 pts · 2y