Hjalmar

u/Hjalamanger@feddit.nu
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You can't send bits at a constant rate in this case. You essentialy get to send one very large number, the amount of time since your decided starting time (plus the one bit we were actually intended to use). The bit count grows logarithmicly with time

Thus, the amount of bits n you can send over t time steps would be

n = log(t)/log(2) + 1

As an example, say they wait 8 seconds before sending you a 1. You have received the number 1000 and the bit 1. That's a total of 5 bits.

If they choose to wait twice as long, 16 seconds, they have in effect transmitted the numbers 10000 and one additional bit, a total of 6 bits. Double the time but only one additional bit.

on Post-glacial rebound · c/wikipedia · 4 pts · 251d

"landhöjning", land raising, we call this in Sweden. Here it's a well known phenomenon here. But it was really cool to see a map, I didn't know it was so much faster in Canada. Also, I didn't know that other parts are moving down due to this

No, as far as I know the convention is to measure by melted height. Although this may be more useful for actually understand how much snow fell. Measured by molten height, the actual snow is about ten times as deep

Edit: I could be wrong, but this is the way that Yr and SMHI measure things

on *Permanently Deleted* · c/comicstrips · 2 pts · 254d

Also, my android phone calculator says 16

So for my intents and purposes, this is ambiguous and dumb but the answer is 16 :)

EDIT: I own a TI calculator

on Casualty of War · c/comicstrips · 9 pts · 258d

Do you make this comic? And the one on analognowhere? I've only really read techno mage (which is amazing) and now I see this one?