Kinky. But no, not necessarily. You could say that one of them is the actual person and the other "person" is just the first person's shadow. It's a stretch, but it's the best I've got.

Pirasp@lemmy.world · 46 pts · 2y (3 replies)

That totally works, but only when Positionen on an appropriately sized sphere

Wilzax@lemmy.world · 20 pts · 2y

🫵 Deutsche

alp@lemmy.zip · 3 pts · 2y (1 reply)

So unless you are a flat earther, you cannot complain?

Pirasp@lemmy.world · 2 pts · 2y

I guess so, also it puts into perspective, how big a feef is. It would have to be 1/4 of the Earth's circumference. Or maybe they are standing on a smaller sphere.

Bezier@suppo.fi · 41 pts · 2y (2 replies)

The meme artist here is not thinking in enough dimensions. These constraints result in a tetrahedron. So you just need to stand in a triangle formation and have the last guy go in the center and float less than the average human height above ground.

TheSlad@sh.itjust.works · 21 pts · 2y (1 reply)

Damn i hate when some other pedant beats me to it in the comments!

TokenBoomer@lemmy.world · 3 pts · 2y

Stephen Hawking isn’t a pedant, he only went to Epstein’s island to get away from light pollution.

AdrianTheFrog@lemmy.world · 27 pts · 2y (2 replies)

It makes sense if you interpret it as ≥6, which is probably what they meant anyways.

Edit: I'm pretty sure it also works in hyperbolic space

dQw4w9WgXcQ@lemm.ee · 27 pts · 2y (1 reply)

I think you're fine in just 3 dimensions. If the person to the upper left and lower right have a separate elevation from the other two, this is basically just the shape of a 4 sided die.

INHALE_VEGETABLES@aussie.zone · 2 pts · 2y

Based.

deadbeef@lemmy.nz · 27 pts · 2y

Solve for feef.

Siegfried@lemmy.world · 22 pts · 2y (1 reply)

Well, that's not practical, but is physically possible, we just need someone moving on stilts and we are done

Magnetar@feddit.de · 10 pts · 2y

Just a simple tetrahedron of people.

mvirts@lemmy.world · 16 pts · 2y (1 reply)

Tetrahedron of safety

NaibofTabr@infosec.pub · 6 pts · 2y

Rhombus of terror?

henfredemars@infosec.pub · 13 pts · 2y (1 reply)

Implying flat Cartesian space.

temmink@feddit.de · 1 pts · 2y

But people exist only on Earth so what do you suggest? Earth being some spinning bouncy ball instead of a majestic plane?

brown567@sh.itjust.works · 12 pts · 2y

But how many feet are in a foof? 🤔

anubis119@lemmy.world · 10 pts · 2y

I never thought I'd need to remember that math equation. Little did I know I'd need it to answer a meme on Lemmy. 8.485.

JusticeForPorygon@lemmy.world · 10 pts · 2y

Approx. 8.5 feet for anyone curious

6√2 if anyone wants to be more specific

RIP_Cheems@lemmy.world · 10 pts · 2y (1 reply)

"FIVE MINUTES. GIVE ME FIVE MINUTES."

nonagonOrc@lemmy.world · 8 pts · 2y

"I JUST WANT TO TALK TO THEM."

xia@lemmy.sdf.org · 6 pts · 2y

It works in three-dimensional space...

rwhitisissle@lemmy.ml · 5 pts · 2y

Everyone's saying that this works in 3 dimensional space, but this also works in 2 dimensional space such that each side could be at a minimum six feet. The resulting structure would be a rhombus and not a square, with the distance between two of the individuals being much greater than 6 feet, though, which the artist did not accurately represent.

finkrat@lemmy.world · 3 pts · 2y

Wait so to maintain social distancing I need to perform a ~~tire~~ people rotation?

thinkyfish@lemmy.world · 3 pts · 2y

Look, lets be honest here, they'd be holding Neil back instead.

LemmyKnowsBest@lemmy.world · 1 pts · 2y (1 reply)

[ removed ]

PipedLinkBot@feddit.rocks · 2 pts · 2y

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Lemjukes@lemm.ee · 1 pts · 2y